What's the charging efficiency?

lorenfb said:

SageBrush said:

lorenfb said:

Assuming 6.6 kW for L-2:

I = 6.6 kW / 360 = 18.3 amps (ideally)

P (battery dissipation) = I^2 X R (battery resistance) = 18.3 ^2 X 60 mohms (.06) = 20 watts (fairly cool on the touch)

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Yes, and presuming a 4 hour charge, 80 Wh of heat into the pack mass. I've looked it up before but have forgotten -- what is the specific heat capacity of the pack ?

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Very negligible temp rise, most likely within the accuracy of measurement.

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