lorenfb wrote:SageBrush wrote:lorenfb wrote:Assuming 6.6 kW for L-2:
I = 6.6 kW / 360 = 18.3 amps (ideally)
P (battery dissipation) = I^2 X R (battery resistance) = 18.3 ^2 X 60 mohms (.06) = 20 watts (fairly cool on the touch)
Yes, and presuming a 4 hour charge, 80 Wh of heat into the pack mass. I've looked it up before but have forgotten -- what is the specific heat capacity of the pack ?
Very negligible temp rise, most likely within the accuracy of measurement.
That is my guess also